140,574 views
31 votes
31 votes
Jonathan sells 3 times as many computers as his friend Mark. If the difference in their sales is 28, how many computers did each sell?

User Nabheet
by
2.6k points

1 Answer

16 votes
16 votes

SOLUTION

Given:

Jonathan sells 3 times as many computers as his friend Mark. If the difference in their sales is 28, how many computers did each sell?


Let\text{ the number of computers sold by Jonathan be j, and that of Mark be m;}
\begin{gathered} From\text{ the given statement;} \\ j=3m----(1) \\ j-m=28---(2) \\ Substitute\text{ j=3m into equation \lparen2\rparen} \\ 3m-m=28 \\ 2m=28 \\ m=(28)/(2) \\ m=14 \\ Substitute\text{ m=14 into equation \lparen1\rparen;} \\ j=3(14) \\ j=42 \end{gathered}

Final answer:


\begin{gathered} Jonathan\text{ sold 42 computers.} \\ Mark\text{ sold 14 computers.} \end{gathered}

User Liu Tao
by
2.6k points