Question

A gas takes up a volume of 17.0 L, has a pressure of 2.30 atm, and a temperature of 299 K. If the temperature is raised to 350.0 K and the pressure lowered to 1.50 atm, what is the new volume of the gas?

Answer 1

Answer: 30.51L

Explanation:

Let's assume the gas is an ideal gas, the equation for ideal gas equation is

PV = nRT

⇒ PV/T = nR

n and R are both constants

Thus for another circumstance of the same gas, it's again P'V'/T' = nR

Thus we can say PV/T = P'V'/T'

Now in the question, P1V1/T1 = P2V2/T2

⇒ (2.3 × 17)/299 = (1.5 × v2)/350

⇒ v2 = 30.51 L