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2loga(3)+loga(5)=loga(x)
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2loga(3)+loga(5)=loga(x)

User Naseema
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2log_a(3)+log_a(5)=log_a(x)\ \ \ \ a>0\ \ and\ \ a \\eq 1\ \ \ \ \ \ \ D=(0;+\infty) \\\\log_a(3^2)+log_a(5)=log_a(x)\\\\log_a(9\cdot5)=log_ax\ \ \ \Leftrightarrow\ \ \ x=45\ \ \in\ D\\\\Ans.\ x=45
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