Part A: Thuy
mean (average) of 2.8, and a standard deviation of 0.8
Thuy's score is 2.5
Calculate the z-score and we have
Therefore, Thuy is -0.375 standard deviations away from the mean.
Part B: Vichet
Doing the same as above, we have the following values
x = 86
μ = 78
σ = 10
Therefore, Vichet is 0.8 standard deviations away from the mean.
Part C: Kamala
x = 8.5
μ = 8.4
σ = 0.5
Therefore, Kamala is 0.2 standard deviations away from the mean.