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What does e^-infinity equal? And what does e^infinity equal?

2 Answers

3 votes

Final answer:

The exponential function e^(-infinity) equals 0, and the exponential function e^(infinity) equals infinity.

Step-by-step explanation:

The exponential function e^(-infinity) equals 0, and the exponential function e^(infinity) equals infinity.

To understand this, let's look at the definition of the exponential function. The number e, approximately equal to 2.71828, is the base of the natural logarithm.

When a positive number is raised to infinity, it becomes infinitely large. That's why e^(infinity) equals infinity. On the other hand, when a positive number is raised to negative infinity, it approaches zero. Therefore, e^(-infinity) equals 0.

User Chevaughn
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Answer to your first question:


\underset { x\rightarrow -\infty }{ lim } { e }^( x )=0

Concerning your second question:

The answer would just be 'positive infinity', or you could say 'undefined' because infinities don't have precise values.
User Ottovsky
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