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(3b-5)^2-c^2 how do I factor this using grouping?
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1 vote
(3b-5)^2-c^2 how do I factor this using grouping?

User TheAtomicOption
by
8.7k points

1 Answer

3 votes
so you see it is the difference of 2 perfect squares
a^2-b^2=(a+b)(a-b)
so
(3b-5)^2-c^2=(3b-5+c)(3b-5-c)
User AshK
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