Question

In an experiment, 3.25 g of C3H8 react with 3.50 g of O2.1) Write the formula for the reactant that is the limiting reactant.

Answer 1

So,

The reaction that takes place here is the next one:

The first thing we're going to do is to pass the mass of each compound to moles. (We do this just dividing by the molecular weight of the compound):

Now, the last step is just to divide each amount by the coefficient of the reaction of each compound. The smaller result will be the limiting reactant.

Therefore, the limiting reactant is O2.