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Is a square of an even number always even? In 1.2 you wrote the general term of sequences you wrote in 1.1.1-1.1.3 If a number is even, it can always be written as 2x another number Eg: 28 = 2 x 14 In symbols we write this as 2 x nor 2n Do you agree with the statement below? "A square of an even number is always even". Explain your answer

Is a square of an even number always even? In 1.2 you wrote the general term of sequences-example-1
Is a square of an even number always even? In 1.2 you wrote the general term of sequences-example-1
Is a square of an even number always even? In 1.2 you wrote the general term of sequences-example-2
Is a square of an even number always even? In 1.2 you wrote the general term of sequences-example-3
User Statosdotcom
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1 Answer

15 votes
15 votes

5)

5.1

Given equation is


P=n^2-n+41

Replace n=1, we get


P=1-1+41=41

We know that a number divisible by one and itself is called a prime number.

Here 41 is divisible by 1 and 41 only.

Hence 41 is a prime number.

5.2.

Substitute n=37 in the equation of P, we get


P=(37)^2-37+41


P=1369-37+41


P=1373

The number 1373 is divisible by one and 1373 only.

So 1373 is a prime number.

Hence if n=37, then P is a prime number.

5.3.

We need to choose three numbers greater than 38.

Let n=39 and substitute in P, we get


P=(39)^2-39+41


P=1521-39+41


P=1523

The number 1523 is divisible by one and 1523.

Hence 1523 is a prime number.

Let n=40 and substitute in P, we get


P=(40)^2-40+41


P=1600-40+41
P=1601

The number 1601 is divisible by one and 1601.

Hence 1601 is a prime number.

Let n=41 and substitute in P, we get


P=(41)^2-41+41
P=1681-41+41


P=1681

The number 1681 is divisible by one and 1681.

Hence 1681 is a prime number.

We get that

When n=39,40 and 41 then P is prime.

5.4)

Yes, I believe that this conjecture is true.

we have chosen n=1, n=39 0dd number, n=40 even number, and n=41 prime number then we get the prime number for P.

So this conjectures is true for any value of n.

The equation P gives the prime number.

User Phonixor
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