Question

A spinner is divided into many sections of equal size. Some sections are red, some are blue, and the remaining are green. The probability of the arrow landing on a section colored red is 11 over 20. The probability of the arrow landing on a section colored blue is 6 over 20. What is the probability of the arrow landing on a green-colored section? 6 over 20 3 over 20 9 over 20 17 over 20

Answer 1

3 over 20

Explanation:

Answer 2

We have 3 sections.


`\sf~Red=(11)/(20)`


`\sf~Blue=(6)/(20)`

So the entire spinner is divided into
`\sf20` sections.

Since we only have 3 sections(red, blue, green) we can add red and blue, and subtract 1 or 20/20.


`\sf(11)/(20)+(6)/(20)\rightarrow(11+6)/(20)\rightarrow(17)/(20)`

Subtract:


`\sf(20)/(20)-(17)/(20)=\boxed{\sf(3)/(20)}`

So the probability that the arrow landing on a green-colored section is
`\sf(3)/(20)`.