Question

Suppose that a certain alloy is made by mixing 300 g of an alloy that contain 72% copper with 20 g of pure copper a) how many grams of copper in the resulting mixture b) in what percentage of the resulting mixture is copper

Answer 1

Answer:

Explanations:

Mass of the alloy = 300 g

Percentage composition of copper in the alloy = 72%

Mass of copper in the alloy = (72/100) x 300

Mass of copper in the alloy = 216 g

The alloy was mixed with 20 g of pure corper

a) Mass of copper in the resulting mixture = (Mass of copper in the alloy) + (Mass of pure corper)

Mass of copper in the resulting mixture = 216 g + 20 g

Mass of copper in the resulting mixture = 236 g

b) In what percentage of the resulting mixture is copper

The mass of the resulting mixture = 300 g + 20 g = 320 g

Percentage of copper in the resulting mixture =

(Mass of copper in the resulting mixture / mass of the resulting mixture) x 100%

Percentage of copper in the resulting mixture = (236 / 320) x 100%

Percentage of copper in the resulting mixture = 73.75%