66,181 views
39 votes
39 votes
I need help filling in the blanks in the problem I appreciate it.

I need help filling in the blanks in the problem I appreciate it.-example-1
User Aaron Deming
by
2.7k points

1 Answer

27 votes
27 votes

The formula for calculating binomial probability is expressed as

P(x) = nCx * p^x * q^(n - x)

where

n represents number of trials

p represents probability of success

q represents probability of failure

x represents number of successes

From the information given,

n = 5

p = 0.479

q = 1 - p = 1 - 0.479 = 0.521

For x = k = 0,

P(x = k = 0) = 5C0 * 0.479^0 * 0.521^(5 - 0)

P(x = k = 0) = 0.0384

For x = k = 1,

P(x = k = 1) = 5C1 * 0.479^1 * 0.521^(5 - 1)

P(x = k = 1) = 0.1765

For x = k = 2,

P(x = k = 2) = 5C2 * 0.479^2 * 0.521^(5 - 2)

P(x = k = 2) = 0.3245

For x = k = 3,

P(x = k = 3) = 5C3 * 0.479^3 * 0.521^(5 - 3)

P(x = k = 3) = 0.2983

For x = k = 4,

P(x = k = 4) = 5C4 * 0.479^4 * 0.521^(5 - 4)

P(x = k = 4) = 0.1371

For x = k = 5,

P(x = k = 5) = 5C5 * 0.479^5 * 0.521^(5 - 5)

P(x = k = 5) = 0.0252

User Shragi
by
3.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.