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4 votes
3x+6y=6
2x-3y=4
Solve the system of equations

User Topaco
by
7.6k points

1 Answer

3 votes
(3x+6y=6) x 2
(2x-3y =4) x 3

Subtract them:

(6x+12y =12)
-(6x - 9y =12)
21y = 0
21 21

y= 0

Using this, we can say that:
3X+6(0)=6 or 3x = 6
2X-3(0)=4 or 2x = 4

So therefore, x must equal 2.

User Jdeng
by
8.5k points

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