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5 votes
What are the solutions to
(m +11)2 = 64?

User Listing
by
3.1k points

2 Answers

8 votes

Answer:

(21 + 11)2 = 64

So, I don't think teachers do this, but this is my way of doing it

Okay, so first, I divided 64 by 2 :

64 ÷ 2 = 32

Then, I subtracted 11 from 32:

21

Now, to check, just do the problem :

(21 + 11)2 = 64

32 * 2 = 64

User Nyi
by
3.8k points
0 votes

Answer:

The solutions are:


m=-3,\:m=-19

Explanation:

Given the expression


\left(m\:+11\right)^2=\:64


\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=√(f\left(a\right)),\:\:-√(f\left(a\right))

solving


m+11=√(64)


m+11=√(8^2)


m+11=8
√(8^2)=8

Subtract 11 from both sides


m+11-11=8-11

Simplify


m=-3

now solving


m+11=-√(64)


m+11=-√(8^2)


m+11=-8
√(8^2)=8

Subtract 11 from both sides


m+11-11=-8-11

Simplify


m=-19

Thus, the solutions are:


m=-3,\:m=-19

User David Ruhmann
by
3.4k points