Question

What Celsius temperature, T2 , is required to change the volume of the gas sample in Part A ( T1 = 35 ∘C , V1 = 1260 L ) to a volume of 2520 L ? Assume no change in pressure or the amount of gas in the balloon.

Answer 1

70 degree celsius

Explanations:

According to Charle's law, the volume of a given mass of gas is directly proportional to absolute temperature provided that the pressure is constant. Mathematically;

`\begin{gathered} v\alpha T \\ v=kT \\ k=(v_1)/(T_1)=(v_2)/(T_2) \end{gathered}`

where

v1 and v2 are the initial and final volume respectively

T1 and T2 are the initial and final temperature respectively

Given the following parameters

`\begin{gathered} v_1=1260L \\ v_2=2520L \\ T_1=35^0C \end{gathered}`

Required

Final temperature T2

Substitute the given parameters into the formula to have:

`\begin{gathered} T_2=(v_2T_1)/(v_1) \\ T_2=(2520*35)/(1260) \\ T_2=70^0C \end{gathered}`

Hence the celsius temperature T2 required is 70 degree celsius