H=45t-4.9t^2 what's the max height?

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asked Jun 2, 2016 9.0k views

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H=45t-4.9t^2 what's the max height?

Mathematics
high-school

David Pratte asked

by David Pratte

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Differentiate to find time that gradient=0 45-9.8t=0 45=9.8t t =4.59 secs put this value into original equation to get 103.31

Amir Karimi answered Jun 8, 2016

by Amir Karimi

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