Question

(x-4)^2+(y+12^2)=17^2 what is the length of its radius

Answer 1

`\text{The standard form equation of a circle is }(x-x_1)^2+(y-y_1)^2=r^2\\\\ (x-4)^2+(y+12)^2=17^2 \\ \Downarrow\\ r^2=17^2\\ r=17`

Answer 2

`(x-4)^(2) + (y+12)^(2) = 17^(2) \\ x^(2) + y^(2) = r^(2) \\ r^(2) = 17^(2) \\ \sqrt{ r^(2) } = \sqrt{ 17^(2) } \\ r=17`