(x-4)^2+(y+12^2)=17^2 what is the length of its radius

asked Jan 10, 2016 121k views

4 votes

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4 votes

$\text{The standard form equation of a circle is }(x-x_1)^2+(y-y_1)^2=r^2\\\\ (x-4)^2+(y+12)^2=17^2 \\ \Downarrow\\ r^2=17^2\\ r=17$

Laquandra answered Jan 11, 2016

8.2k points

3 votes

$(x-4)^(2) + (y+12)^(2) = 17^(2) \\ x^(2) + y^(2) = r^(2) \\ r^(2) = 17^(2) \\ \sqrt{ r^(2) } = \sqrt{ 17^(2) } \\ r=17$

Kishori answered Jan 16, 2016

7.2k points

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