Question

the perimeter of a rectangle is 66 cm and its width is half its length. what are the length and the width of the rectangle?

Answer 1

P = 2(l + w)

w = l/2

Plug in 'l/2' for 'w' in the equation with '66':

66 = 2(l + l/2)

66 = 2l + 2l/2

66 = 2l + l

66 = 3l

22 = l

So the length is 22.

Now plug this in to find the width.

66 = 2(22 + w)

66 = 44 + 2w

22 = 2w

11 = w

So the width is 11, and the length is 22.

Answer 2

Let's set width = w

Then length = 2w

We can set up the equation:


`2(w+ 2w) = 66`


`2(3w) = 66`


`6w = 66`


`w = (66)/(6) = \boxed{11}`

Then we plug in:


`l = 2w = 2(11) = \boxed{22}`

Hope this helps :)