Question

What is the heat transference when 500 g of copper (C=0.385.J/g^ C) goes from 35.0 degrees * C to 25.0 degrees * C

Answer 1

Step-by-step explanation:

Here, we want to get the amount of heat transferred

We can get that with the following formula:

`Q\text{ = mc}\Delta\theta`

where:

`\begin{gathered} Q\text{ = quantity of heat} \\ m\text{ = mass of the copper - 500g} \\ \Delta\theta\text{ = (25-35) = -10 deg. celsius} \\ c\text{ = 0.385 J/gC} \end{gathered}`

Substituting these values, we have it that:

`Q\text{ = 500}*0.385*(-10\text{ )= -1,925 J}`

We have a negative answer as we are moving from a higher to a lower temperature which indicates a heat loss