Question

Can someone help me with this equation. I am unable to get the paper version because of my quarantine and am looking for extra help.

Answer 1

The quadaratic equation is given below as

`x^2+4x=18`

Step 1:

Take half of the x term and square it

`(4*(1)/(2))^2=2^2=4`

Then add the result to both sides

Hence, We will have

`x^2+4x+4=18+4`

Step 2:

Rewrite the perfect square on the left

Hence,

We will have

`(x+2)^2=22`

Step 3:

Take the square root of both sides, we will have

`\begin{gathered} x+2=√(22) \\ x+2=\pm4.7 \end{gathered}`

Step 4:

Isolate the x on the left side and

solve for x (1)

`\begin{gathered} x+2=4.7 \\ x=4.7-2 \\ x=2.7 \\ \\ x+2=-4.7 \\ x=-4.7-2 \\ x=-6.7 \end{gathered}`

Hence,

The final answers will be shown in the image below