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Solve using substitution. 4a=3b+3 a=b-1
asked
Oct 25, 2016
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Solve using substitution.
4a=3b+3
a=b-1
Mathematics
high-school
Octavio Del Ser
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4
a=3b+3
Put a=b-1 in the above equation
4(b-1) = 3b+3
open the brackets
4b - 4 = 3b + 3
collect B-terms together on one side
4b - 3b = 3+4
b = 7
Krzyhub
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Oct 26, 2016
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Krzyhub
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4
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4(b-1)=3b+3
4b-4=3b+3 -- subtract 3b from both sides
b-4=3 -- add 4 to both sides
b=7
Substitute b into equation 2
a=b-1
a=7-1
a=6
Verify:
4(6)=3(7)+3
24=21+3
24=24 -- True.
Xenonite
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Oct 29, 2016
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Xenonite
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