Question 1

21. What is the total surface area of the figure below? Total S.A. =cm?4 cm8 cm6 cm4 cm4 cm6th Period6 cm

Question 2

If the figure is divided into 6 rectangles, the total area will be as follows:

A= area

Rectangle 1 and 3:

b= 8cm

h= 4cm

$\begin{gathered} A_(R1)=\text{ b}* h \\ A_(R1)=8*4\text{ = 32} \\ A_(R1)=32\operatorname{cm} \\ As\text{ there are two with the same mesures:} \\ A_(R1,3)=2*32\operatorname{cm}=64\operatorname{cm} \end{gathered}$

Rectangle 2 and 4:

b= 8cm

h= 6cm

$\begin{gathered} A_(R2)=\text{ b}* h \\ A_(R2)=8*6\text{ = }48 \\ A_(R2)=48\operatorname{cm} \\ As\text{ there are two with the same mesures:} \\ A_(R2,4)=\text{ 2}*48\operatorname{cm}=96cm^2 \end{gathered}$

Lateral Rectangle:

b= 6cm

h= 4cm

$\begin{gathered} A_(LR)=\text{ b}* h \\ A_(LR)=6*4\text{ = }24 \\ A_(LR)=24\operatorname{cm} \\ As\text{ there are two lateral rectangles:} \\ A_(LR)=2*24\operatorname{cm}=48\operatorname{cm} \end{gathered}$

Total Area (TA):

$\begin{gathered} A_T=A_(R1,3)+A_(R2,4)+A_(LR) \\ A_T=64\operatorname{cm}+96\operatorname{cm}+48\operatorname{cm} \\ A_T=208\operatorname{cm} \end{gathered}$

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