Question

What are the factors of 3x²+7x-20?

Answer 1

`3x^2+7x-20=0\\\\a=3;\ b=7;\ c=-20\\\\\Delta=b^2-4ac\\\\x_1=(-b-\sqrt\Delta)/(2a);\ x_2=(-b+\sqrt\Delta)/(2a)\\\\\Delta=7^2-4\cdot3\cdot(-20)=49+240=289;\ \sqrt\Delta=√(289)=17\\\\x_1=(-7-17)/(2\cdot3)=(-24)/(6)=-4;\ x_2=(-7+17)/(2\cdot3)=(10)/(6)=(5)/(3)\\\\\\3x^2+7x-20=3(x+4)(x-(5)/(3))\\\\\\3x^2+7x-20=0\iff x=-4\ \vee\ x=(5)/(3)`