Question

Based on the balanced chemical reaction, if you desired to produce 2.50g of NaCI in this reaction, how many grams of Na2CO3 would need to be used. Na2CO3 105.99NaCI 2.50g58.44g NaCl

Answer 1

Na2CO3 (s) + 2 HCl (aq) ---> 2 NaCl (aq) + H2O (l) + CO2 (g)

First you must balance the reaction:

Number of atoms on the left = Number of atoms on the right

Na2CO3 (s) + 2 HCl (aq) ---> 2 NaCl (aq) + H2O (l) + CO2 (g)

x 2.50 g

x is the unknown we are looking for. It is the mass of the Na2CO3 we need to use to produce 2.50 g of NaCl.

We know from the reaction that:

1 mol of Na2CO3 = 105.99 g

1 mol of NaCl = 58.44 g

The next is:

105.99 g Na2CO3 ----------------- 2 x 58.44 g NaCl

x ------------------ 2.50 g NaCl

`x\text{ = }\frac{2.50\text{ g NaCl x 105.99 g Na2CO3}}{2\text{ x 58.44 g NaCl}}=\text{ 1.81 g Na}2CO3`

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