Na2CO3 (s) + 2 HCl (aq) ---> 2 NaCl (aq) + H2O (l) + CO2 (g)
First you must balance the reaction:
Number of atoms on the left = Number of atoms on the right
Na2CO3 (s) + 2 HCl (aq) ---> 2 NaCl (aq) + H2O (l) + CO2 (g)
x 2.50 g
x is the unknown we are looking for. It is the mass of the Na2CO3 we need to use to produce 2.50 g of NaCl.
We know from the reaction that:
1 mol of Na2CO3 = 105.99 g
1 mol of NaCl = 58.44 g
The next is:
105.99 g Na2CO3 ----------------- 2 x 58.44 g NaCl
x ------------------ 2.50 g NaCl
![x\text{ = }\frac{2.50\text{ g NaCl x 105.99 g Na2CO3}}{2\text{ x 58.44 g NaCl}}=\text{ 1.81 g Na}2CO3](https://img.qammunity.org/qa-images/2023/formulas/chemistry/college/9q1319jjtqdw7az69lt3.png)
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