Question

What is the 50th term of the arithmetic sequence 4, 10, 16, 22, … ?

Can someone explain this one?

Answer 1

298, also 4 is first term. 49 terms left. 49*6=294
294+4=298

Answer 2

The equation appropriate for this is

`a_(n)=a_(1)+(n-1)d`
Wherein
`_(n)` is the missing term,
`a_(1)` is the first number in the sequence, and
`d` is the difference between the numbers.
So
`a_(50)=4+(50-1)6`

`a_(50)=4+(49*6)`

`a_(50)=4+(294)`

`a_(50)=298`
*Sorry for the error.