Question

The perimeter of a square is 32 feet. Find the length of one of the diagonals

Answer 1

The length it's 8 feet .

Answer 2

32/4 is 8, so we know that the lengths of the sides are 8 feet.

Because of this I can safely say that the diagonal of the square is 8√2 feet long.

Here's my proof:


`c=\sqrt { { 8 }^( 2 )+{ 8 }^( 2 ) } \\ \\ =\sqrt { 64+64 } \\ \\ =\sqrt { 64\cdot 2 } \\ \\ =\sqrt { 64 } \sqrt { 2 } \\ \\ =8\sqrt { 2 }`