Question

A car starts from rest and accelerates at a rate of 1.15m/s^2 How far must the car travel to reach a speed of 2.5 m/s?

Answer 1

Given data

*The given initial speed of the car is u = 0 m/s

*The given acceleration of the car is a = 1.15 m/s^2

*The given final speed of the car is v = 2.5 m/s

The formula for the distance travelled by the car is given by the kinematic equation of motion as

`\begin{gathered} v^2=u^2+2as \\ s=(v^2-u^2)/(2a) \end{gathered}`

Substitute the known values in the above expression as

`\begin{gathered} s=((2.5)^2-(0)^2)/(2(1.15)) \\ =2.71\text{ m} \end{gathered}`

Hence, the distance travelled by the car is s = 2.71 m