203k views
3 votes
Write an equation in point-slope form of the line through the given points. Then write the equation in slope-intercept form.

(-10,-6);m = -5/8

User Badp
by
8.1k points

1 Answer

6 votes

y-y_1=m(x-x_1) \\ \\ m=-(5)/(8) \\ (-10,-6) \\ x_1=-10 \\ y_1=-6 \\ \Downarrow \\ y-(-6)=-(5)/(8)(x-(-10)) \\ \boxed{y+6=-(5)/(8)(x+10)} \ - \ \hbox{the point-slope form} \\ \\ y+6=-(5)/(8)(x+10) \\ y+6=-(5)/(8)x-(50)/(8) \\ y=-(5)/(8)x-(50)/(8)-6 \\ y=-(5)/(8)x-(25)/(4)-(24)/(4) \\ y=-(5)/(8)x-(49)/(4) \\ \boxed{y=-(5)/(8)x-12 (1)/(4)} \ - \ \hbox{the slope-intercept form}
User DirkyJerky
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories