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How many moles of N₂ are essential for generating 0.08 moles of Li₃N in the given reaction? 6Li + N₂ 2Li₃N 0.013 moles 0.04 moles 0.08 moles 0.16 moles 0.48 moles
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Jul 2, 2017
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How many moles of N₂ are essential for generating 0.08 moles of Li₃N in the given reaction?
6Li + N₂ 2Li₃N
0.013 moles
0.04 moles
0.08 moles
0.16 moles
0.48 moles
Chemistry
high-school
SteveTurczyn
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Each mole of N₂ generates 2 moles of Li₃N. Thus,
0.08 moles of Li₃N will require:
0.08 / 2
= 0.04 moles of N₂
The second option is correct.
Danieljames
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Jul 8, 2017
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Danieljames
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