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How many moles of N₂ are essential for generating 0.08 moles of Li₃N in the given reaction?

6Li + N₂ 2Li₃N

0.013 moles

0.04 moles

0.08 moles

0.16 moles

0.48 moles

1 Answer

5 votes
Each mole of N₂ generates 2 moles of Li₃N. Thus,
0.08 moles of Li₃N will require:
0.08 / 2
= 0.04 moles of N₂

The second option is correct.
User Danieljames
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