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What is the result when we simplify the expression ( 1 + 1 x ) ( 1 − 2 x + 1 ) ( 1 + 2 x − 1 ) ( 1 + 1 x ) ( 1 − 2 x + 1 ) ( 1 + 2 x − 1 ) ?

User McLaren
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2 Answers

7 votes

Answer:

x+1/x

Explanation:

User Yole
by
8.3k points
0 votes

Answer:


4x^2\left(x+1\right)^2\left(-2x+2\right)^2

Explanation:


\left(1+1\cdot \:x\right)\left(1-2x+1\right)\left(1+2x-1\right)\left(1+1\cdot \:x\right)\left(1-2x+1\right)\left(1+2x-1\right)


=\left(1+1\cdot \:x\right)\left(1+2x-1\right)\left(1+1\cdot \:x\right)\left(1-2x+1\right)^(1+1)\left(1+2x-1\right)


=\left(1+2x-1\right)\left(1+1\cdot \:x\right)^(1+1)\left(1-2x+1\right)^2\left(1+2x-1\right)


=\left(1+2x-1\right)\left(1+1\cdot \:x\right)^(1+1)\left(1-2x+1\right)^2\left(1+2x-1\right)


=\left(1+2x-1\right)\left(1+1\cdot \:x\right)^2\left(1-2x+1\right)^2\left(1+2x-1\right)


=\left(1+1\cdot \:x\right)^2\left(1-2x+1\right)^2\left(1+2x-1\right)^(1+1)


=\left(x+1\right)^2\left(-2x+1+1\right)^2\left(2x+1-1\right)^2


=\left(x+1\right)^2\left(-2x+2\right)^2\left(2x+1-1\right)^2


=2^2x^2\left(x+1\right)^2\left(-2x+2\right)^2


=4x^2\left(x+1\right)^2\left(-2x+2\right)^2

Hope I helped you!

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User Prayag Gordy
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