Question

Prove: An odd plus an oddequals an even.(2m + 1) + (2n + 1) = [ ] m + [ ]n + [ ]=2 (m+n+[ ])= even

Answer 1

EXPLANATION :

We need to prove that an odd number plus an odd number is an even number.

Note that an odd number can be written as (2x + 1)

From the problem, we have two odd numbers :

`(2m+1)+(2n+1)=\_m+\_n+\_`

Simplify the expression :

`(2m+1)+(2n+1)=2m+2n+2`

Factor out 2 :

`=2(m+n+1)`

Note that any number multiplied by 2 is always an even number.

Therefore, the sum is even.