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What is the gravitational potential energy of a 0.1 kg apple sitting on top of a 12.5 m flagpole? Note: GPE= mgh. m= mass, g= acceleration due to gravity (9.8 m/s^2), h= objects height above the ground.
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What is the gravitational potential energy of a 0.1 kg apple sitting on top of a 12.5 m flagpole? Note: GPE= mgh. m= mass, g= acceleration due to gravity (9.8 m/s^2),
h= objects height above the ground.
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Edward Newsome
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GPE= mgh = 0.1 kg * 9.8 m/s^2 * 12.5m = 12.25 J
Sweeney
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Nov 7, 2017
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