Question

How do I find the slope and Y-Intercept to this gragh?

Answer 1

Using the two points given: (-1,-1) and (2,-2) you can create a linear equation in the form y=mx+b where m is the slope and b is the y intercept.

Creating a system of equations plugging in the two known points:

-1=m(-1)+b

-2=m(2)+b


Solving the first equation for b, you get b=-1+m, plugging this value in for b in the second equation, you get:

-2=m(2)+(-1+m)
-2=2m-1+m
-2=3m-1
-1=3m
m=
`(-1)/(3)`

b=-1+m
b=-1+
`(-1)/(3)`
b=-4/3=-1.33

y=mx+b
y=
`(-1)/(3)x- (4)/(3)`

m is the slope, b is the y intercept

Answer 2

slope = rise/run =( -2+1) /( 2 + 1) = -1/3