Congruence - SSS theoremIll send a picture of the question

Krrishna asked Aug 25, 2023

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Krrishna asked Aug 25, 2023

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20 votes

From the figure,

We need to prove that,

$\Delta\text{MNO}\cong\Delta\text{PQR}$

By SSS theorem,

$\begin{gathered} MN\cong PQ(\text{Given)} \\ NO\cong QR(\text{Given)} \end{gathered}$

So, the third side must be,

$MO\cong PR$

Hence, the correct option is D.

Tony Trozzo answered Aug 31, 2023

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