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19 votes
19 votes
The graphs below are both absolute value functions. The equation of the redgraph is f(x) = [x]. Which of these is the equation of the blue graph, g(x)?fx) = x1y5-Xg(x) = ?-55-5O A. g(x) = 1/4O B. g(x) = (x - 21O C. g(x) = (x + 21O D. g(x) = 21x1

User Andrew Ingram
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1 Answer

23 votes
23 votes

Let's begin by listing out the information given to us:


\begin{gathered} RedGraph\colon f\mleft(x\mright)=|x| \\ \Rightarrow y=|x| \end{gathered}

For the Blue Graph, let's pick 4 coordinates along the line to determine the equation of the graph"


\begin{gathered} (x,y)=(-2,1),(0,0),(2,1),(4,2) \\ |x|=2y\Rightarrow y=(1)/(2)|x| \end{gathered}

We will proceed thus:


\begin{gathered} y=(1)/(2)|x| \\ g(x)=(1)/(2)|x| \\ when,x=-2 \\ g(-2)=(1)/(2)|-2|=1 \\ when,x=0 \\ g(0)=(1)/(2)|0|=0 \\ when,x=2 \\ g(2)=(1)/(2)|2|=1 \\ when,x=4 \\ g(4)=(1)/(2)|4|=2 \\ \\ \therefore g(x)=(1)/(2)|x| \end{gathered}

User Taranjeet Singh
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