Question

A 521-kg meteor is subject to a force of 2520 N. What is its acceleration?

Answer 1

put it in the equation a=f/m

Answer 2

Acceleration,
`a=4.83\ m/s^2`

Step-by-step explanation:

It is given that,

Mass of the meteor, m = 521 kg

Force acting on the meteor, F = 2520 N

Let a is the acceleration of the meteor. It can be calculated using the Newton's second law of motion. According to this law the force acting on an object is equal to the product of mass and acceleration with which it is moving. Mathematically, it is given by :

`F=m* a`

`a=(F)/(m)`

`a=(2520\ N)/(521\ kg)`

`a=4.83\ m/s^2`

So, the acceleration of the meteor is
`4.83\ m/s^2`. Hence, this is the required solution.