Question

A rectangular room is 4 meters longer than it is wide, and its perimeter is 28 meters. Find the dimension of the room.

Answer 1

The width of the room is 5 meters, and the length is 9 meters.

Step-by-step explanation:

To find the dimensions of the rectangular room, let's assign variables. Let x be the width of the room. Since the length is 4 meters longer than the width, we can represent the length as x + 4.

Given that the perimeter is 28 meters, we can write an equation: 2(x + 4) + 2x = 28.

Simplifying the equation, we get 4x + 8 = 28. Subtracting 8 from both sides gives 4x = 20. Dividing both sides by 4, we find x = 5. The width of the room is 5 meters, and the length is 5 + 4 = 9 meters.

Answer 2

Answer: The width of the room = 5 meters

The length of the room = 9 meters

Step-by-step explanation:

Let the w denotes the width of the room , then length of the room will be :-

`\text{length}=4+w`

The formula of perimeter of rectangle :-

`\text{Perimeter}=2(l+w)\\\\\Rightarrow\ 28=2(4+w+w)\\\\\Rightarrow\ 28=2(4+2w)\\\\\Rightarrow\ 28 =8+4w\\\\\Rightarrow\ 4w=20\\\\\Rightarrow\ w=5`

Hence, The width of the room = 5 meters

The length of the room = 5+4 = 9 meters