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Completing the square x^2-19x-42=0

User MerklT
by
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2 Answers

7 votes

Answer:


{x}^(2) - 19x - 42 = 0 \\ {x}^(2) + 2x - 21x - 42 = 0 \\ x(x + 2) - 21(x + 2) = 0 \\ (x + 2)(x - 21) = 0 \\ \boxed{x = - 2} \\ \boxed{x = 21}

(x+2) and (x-21) is the factors of the x²-19x-42.

Value of x is -2 and 21.

User Verma
by
7.3k points
11 votes

Answer:

x = 2

x = -21

Explanation:

User Sanket Pandya
by
8.5k points

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