Question

Completing the square x^2-19x-42=0

Answer 1

`{x}^(2) - 19x - 42 = 0 \\ {x}^(2) + 2x - 21x - 42 = 0 \\ x(x + 2) - 21(x + 2) = 0 \\ (x + 2)(x - 21) = 0 \\ \boxed{x = - 2} \\ \boxed{x = 21}`

(x+2) and (x-21) is the factors of the x²-19x-42.

Value of x is -2 and 21.

Answer 2

x = 2

x = -21

Explanation: