Question

Log4 (x+4) = 1 ?

I assume you distribute log base of four to (x+4). But I don't know how to go about it, please help!!

Answer 1

remember

`log_ab=c` means
`a^c=b`
so


`log_4(x+4)=1` means
`4^1=x+4`
4=x+4
minus 4 both sides
x=0

a fun tip is
if you get
`log_a(b)=1`, then a=b

Answer 2

Log rule:
`\log_a(b)=x\leftrightarrow a^x=b`
By that rule,
`\log_4(x+4)=1\leftrightarrow 4^1=x+4`
We know that
`4^1=4` so we now have
`4=x+4`
Subtract 4 from both sides and you get x=0.