117k views
1 vote
Given the equations 2x + 2y = 16 and 4x - 3y = -3, what are the values of x and y?

User Ul
by
7.5k points

1 Answer

2 votes
Steps:
1. Put 2x + 2y=16 into slope-intercept form
2. Subtract 2x on both sides
2y= -2x + 16
3. Divide by 2 on both sides
Y= -x + 8
4. Substitute the y in 4x -3y=-3 for -x + 8
4x -3(-x + 8)= -3
5. Multiply everything in parentheses
4x + 3x + (-24)= -3
7x + (-24)=-3
6. Add 24 on both sides
7x=21
7. Divide by 7
8. X= 3
9. Substitute the x for a 3 in one of the equations
Y=-x + 8
Y= -3 + 8
Y=5
10. Your answers are
X= 3 Y= 5

User Bacardi
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories