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What is the ideal speed to take a 105 m radius curve banked at a 30.0° angle? m/s

What is the ideal speed to take a 105 m radius curve banked at a 30.0° angle? m/s-example-1
User KFunk
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1 Answer

22 votes
22 votes

We know that the banked curve formula is given by:


\begin{gathered} \tan\theta=(v^2)/(rg) \\ \text{ where} \\ \theta\text{ is the angle} \\ v\text{ is the velocity } \\ r\text{ is the radius } \\ g\text{ is the gravitational acceleration} \end{gathered}

Plugging the values given and solving for v:


\begin{gathered} \tan30=(v^2)/((105)(9.81)) \\ v^2=(105)(9.81)\tan30 \\ v=√((105)(9.81)\tan30) \\ v=24.4 \end{gathered}

Therefore, the ideal speed is 24.4 m/s

User Naga Harish M
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