Register
An alloy of tin and copper contains 16% tin. How much tin (to the nearest tenth) must be added to make 820 pounds of alloy that is 18% tin?
102k views
2 votes
An alloy of tin and copper contains 16% tin. How much tin (to the nearest tenth) must be added to make 820 pounds of alloy that is 18% tin?

User Hdogan
by
8.4k points

1 Answer

5 votes
As we adding the tin only then the difference would be
820-x = 147.6 - .16x

.84x = 672.4

x = 800.48
difference = 820 - 800.48
= 19.52
User Mushfiq
by
8.7k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

Other Questions

Compare and contrast an electric generator and a battery??
How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O
Can someone complete the chemical reactions, or write which one do not occur, and provide tehir types? *c2h4+h2o *c3h8 + hcl *c2h2+br2 *c4h10+br2 *c3h6+br2
As an object’s temperature increases, the ____________________ at which it radiates energy increases.
Why is gold preferred as a superior metal over silver and bronze?
Link Copied!