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An alloy of tin and copper contains 16% tin. How much tin (to the nearest tenth) must be added to make 820 pounds of alloy that is 18% tin?
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An alloy of tin and copper contains 16% tin. How much tin (to the nearest tenth) must be added to make 820 pounds of alloy that is 18% tin?

User Hdogan
by
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1 Answer

5 votes
As we adding the tin only then the difference would be
820-x = 147.6 - .16x

.84x = 672.4

x = 800.48
difference = 820 - 800.48
= 19.52
User Mushfiq
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8.7k points
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