Question

suppose that a superball dropped from a height of 50ft always rebounds 1/5 of the distance fallen. approximately how far does the ball travel before coming to rest?

Answer 1

62.48 ft.

Explanation:

Initial height: 50 ft.

1. First rebound: 10 ft.
2. Second rebound: 2 ft.
3. Third rebound: 0.4 ft.
4. Fourth rebound: 0.08 ft.

If we approximate the fourth rebound to zero, we'll have:

50 + 10 + 2 + 0.4 + 0.08 = 62.48 ft.

Answer 2

The answer is 50ft......

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