Question

What is the concentration of hydrogen ions in a liter of vinegar that has a pH level of 2.5?

Answer 1

Step-by-step explanation

We are told that the vinegar has a pH level of 2.5

To get the hydrogen ion concentration using the properties of the Algorithm

We will substitute the values of PH =2.5 into the equation so that we will have

`2.5=log(1)/(H^(^+))`

We will make

`H^+`

The subject of the formula

To do so, we will find the antilog of both sides

`10^(2.5)=(1)/(H^(^+))`

Making H the subject of the formula

Thus

`\begin{gathered} H^+=\frac{1}{10^{^(2.5)}} \\ \\ H^+=10^(-2.5) \end{gathered}`

Thus, the answer is

`H^+=10^(-2.5)`

Option B is correct