Question

Duncan knows that it takes 36400 cal of energy to heat a pint of water from room temperature to boiling. However, Duncan has prepared ramen noodles so many times he does not need to measure the water carefully. If he happens to heat 0.600 pint of room-temperature water, how many kilojoules of heat energy will have been absorbed by the water at the moment it begins to boil?

Answer 1

(0.600 x 36400) = 21840

1 cal = 4,184 joules

21,840 cal = 91,378.56 Joules (or around 91 kJ)

so 0.600 pit require 91 kJ to boil from Rtp

hope this helps