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A ball is fired vertically into the air. Its height in feet t seconds later is given by the formula: h(t)= -2t^2+80t

a) what is the height of the ball after 3 sec?
b) what is the velocity of the ball after 5 sec?
c) when does the ball reach its man height?
d) what is the max height the ball reaches?

User Pawni
by
7.8k points

1 Answer

6 votes

v(t)=40-16t
so max height is when v(t)=0 or t=40/16
and the max height is found by plugging that into the height equation
User Gonutz
by
8.7k points
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